In Class 12 Boards there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Downloads of CBSE Class 12 Chemistry Chapter 2 Solutions Case Study and Passage-Based Questions with Answers were Prepared Based on the Latest Exam Pattern. Students can solve NCERT Class 12 Chemistry Case Study Questions Solutions to know their preparation level.
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In CBSE Class 12 Chemistry Paper, There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.
Solutions Case Study Questions With Answers
Here, we have provided case-based/passage-based questions for Class 12 Chemistry Chapter 2 Solutions
Case Study/Passage-Based Questions
Case Study 1: At 298 K, the vapour pressure of pure benzene, C6H6 is 0.256 bar and the vapour pressure of pure toluene C6H5CH3 is 0.0925 bar. Two mixtures were prepared as follows:
(i) 7.8 g of C6H6Â + 9.2 g of toluene
(ii)Â 3.9 g of C6H6Â + 13.8 g of toluene
The following questions are multiple-choice questions. Choose the most appropriate answer:
(i) The total vapour pressure (bar) of solution 1 is
| (a) 0.128 | (b) 0.174 | (c) 0.198 | (d) 0.258 |
Answer: (b) 0.174 ​​
(ii) Which of the given solutions has higher vapour pressure?
| (a) I | (b) II |
| (c) Both have an equal vapour pressure | (d) Cannot be predicted |
Answer: (a) I ​​
(iii) Mole fraction of benzene in vapour phase in solution 1 is
| (a) 0.128 | (b) 0.174 | (c) 0.734 | (d) 0.266 |
Answer: (c) 0.734 ​​
(iv) Solution I is an example of a/an
| (a) ideal solution | (b) non-ideal solution with a positive deviation |
| (c) non-ideal solution with a negative deviation | (d) can’t be predicted |
Answer: (a) ideal solution ​​
Case Study 2: The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, the sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 20°C is 17.5 mm of Hg.)
(i) Relative lowering of vapour pressure for the given solution is
| (a) 0.00348 | (b) 0.061 | (c) 0.122 | (d) 1.75 |
Answer: (a) 0.00348 ​​
(ii) The vapour pressure (mm of Hg) of solution will be
| (a) 17.5 | (b) 0.61 | (c) 17.439 | (d) 0.00348 |
Answer: (c) 17.439 ​​
(iii) Mole fraction of sugar in the solution is
| (a) 0.00348 | (b) 0.9965 | (c) 0.061 | (d) 1.75 |
Answer: (a) 0.00348 ​​
(iv) The vapour pressure (mm of Hg) of water at 293 K when 25 g of glucose is dissolved in 450 g of water is
| (a) 17.2 | (b) 17.4 | (c) 17.120 | (d) 17.02 |
Answer: (b) 17.4 ​​
Case Study 3: The concentration of a solute is very important in studying chemical reactions because it determines how often molecules collide in solution and thus indirectly determines the rate of reactions and the conditions at equilibrium. There are several ways to express the amount of solute present in a solution. The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution. Concentration can be expressed in terms of molarity, molality, parts per million, mass percentage, volume percentage, etc.
(i) The molarity (in mol L-1) of the given solution will be
| (a) 1.56 | (b) 1.89 | (c) 0.263 | (d) 1.44 |
Answer: (d) 1.44 ​​
(ii) Which of the following is temperature dependent?
| (a) Molarity | (b) Molality |
| (c) Mole fraction | (d) Mass percentage |
Answer: (a) Molarity ​​
(iii) Which of the following is true for an aqueous solution of the solute in terms of concentration?
| (a) 1 M = 1 m | (b) 1M > 1m |
| (c) 1M < 1 m | (d) Cannot be predicted |
Answer: (b) 1M > 1m ​​
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